You may remember this heptagon figure from a few weeks ago. One consequence of the solution was that the circle shown here, whose diameter endpoints are also extended intersections of pairs of sides of the heptagon, also passes through two midpoints of sides of the heptagon.

As it happens, for a regular heptagon there is another distinct way in which you can draw a circle whose diameter endpoints are extended intersections of the sides, and which also passes through midpoints of sides.

By distinct I mean not just merely a rotation of the circle shown. The other circle will have a different diameter to the one shown.

If the circle shown has a diameter of 6296, what is the diameter of the other possible circle (to the nearest unit)?

Alternatively, if you don’t want to do the numbers, just send me a sketch of the alternative circle.